Question

What will be Q1 in foll case
20-40 6
40-60 8
60-80 9
80-100 13
100-120 16
120-140 18
140-160 12
160-180 6
180-200 3
200-220 1

Answer 1

Answer:

Explanation:

Mean=  

f  

i

​

 

∑f  

i

​

x  

i

​

 

​

=  

50

7260

​

=145.2

⇒  We have, N=50. Then,  

2

N

​

=25.

⇒  Median class is 120−140

l= lower limit of the modal class

h= size of the class intervals

f= frequency of the modal class

f  

1

​

= frequency of the class preceding the modal class

f  

2

​

= frequency of the class succeed in the modal class.

⇒  So, l=120,h=20,N=50cf=12,f=14.