What will be the acceleration due to gravity on the surface of the moon, if its radius is
1/4th the radius of the earth and its mass is 1/80 times the mass of the earth
TNSCERT Class 10 Physics Ch 15 Laws of Motivation and Gravitation
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acc due to gravity on earth g is given by formula g earth = GM/R^2
where G is universal gravitational constant M mass of earth R radius of earth
for moon mass m = mass of earth/80= M/80 radius is r = radius of earth /4 = R/4
g of moon = Gm/r^2
put small m = M/80 and r= R/4
we get (R/4)^2 =R^2/16
g moon =16GM/80R^2
as we know GM/R^2 = g of earth so g moon = g of earth/5 ( g of earth is 9.8m/s^2 or u can say 10)
so g moon = 10/5
g moon =2 ( which means 5 times less than that of g of earth)
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