Question

what will be the accleration of the body of mass 400 grams when a force of 4N acts on it ? what will be it's velocity after 5 seconds if it start from rest​

Answer 1

• Mass=400g=0.4kg
• Force=4N

Using Newtons second law

$\boxed{\sf Force=Mass\times Accleration}$

$\\ \sf\longmapsto Acceleration=\dfrac{Force}{Mass}$

$\\ \sf\longmapsto Acceleration=\dfrac{4}{0.4}$

$\\ \sf\longmapsto Acceleration=0.1m/s^2$

Answer 2

Answer:

$\green {\boxed{ \sf \: acceleration \: a = 10 \: m {s}^{ - 2} }} \\ \\ \green{ \boxed{ \: \sf velocity \: v = 50 \: m {s}^{ - 1} }} \:$

Explanation:

Given,

$\rightarrow \sf \:mass \: of \: body \: \: m = 400 \: g \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf= \frac{4 00 }{1000} \: kg\\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf \: \: \: \: = 0.4 \: kg \\ \\ \rightarrow \sf \:force \: \: F = 4 \: N \\ \rightarrow \sf \:initial \: velocity \: \: u = 0 \: m {s}^{ - 1} \\ \rightarrow \sf \:time \: \: t = 5 \: s$

To find :

$\pink{\rightarrow \sf \:accelartion \: \: = a} \\ \pink{\rightarrow \sf \: </strong><strong>f</strong><strong>i</strong><strong>n</strong><strong>a</strong><strong>l</strong><strong>\</strong><strong>:</strong><strong>velocity = \: \: v}$

Formula :

$\rightarrow \ \: \: \bf \: F = ma \\ \rightarrow \bf \: v = u + at$

Solution :

$\sf \: F = ma \\ \therefore \sf \: a = \frac{F}{m} \\ \sf \: \: \: \: \: \: \: \: = \frac{4}{0.4} \\ \: \: \: \: \: \: \: \: = 10 \: m {s}^{ - 2} \\ \\ \green {\boxed{\therefore \sf \: acceleration \: a = 10 \: m {s}^{ - 2} }}$

Again,

$\sf \: v = u + at \\ \: \: \: \: \sf = 0 + 10 \times 5 \\ \sf \: \: \: \: = 50 \: m {s}^{ - 1} \\ \\ \green{ \boxed{\therefore \: \sf velocity \: v = 50 \: m {s}^{ - 1} }}$