Question

what will be the ans of this que
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Answer 1

Least count =range/no. Of divisions

In ammeter

L. C=100/10=10mA

In voltmeter

L. C=1/10=0.1V

Current in ammeter= 10mA

Converting it to A=10*10^-3 A

So, as the pointer is on 25th division of ammeter (from 0to 100)

=25*10*10^-3

=0.25A

Reading of voltmeter =24*0.1

24th division from 0 to 2.4

=2.4 V

V=IR

2.4/0.25=R

9.6 ohm=R

Hence the resistance is 9.6 ohm

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