what will be the answer mates ????
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Answer:40 degree
angle ABC= angle DCE
angle DCE+angle ECF
such that: angle ECF becomes 110 degree
then
CEF+EFC+ECF=180
30+EFC+110=180
EFC=40
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Since AB 'II' CD
Angle ABC = Angle DCE = 70 ( Corresponding angles )
Now by exterior anglr property,
angle CEF + angle EFD = angle DCE
angle EFD + 30 = 70
angle EFD = 70 - 30
angle EFD = 40
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