Question

what will be the answer of
x²-4√2x+6=0
if it is solved by general method
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Answer 1

answer: x = √2,3√2

explanation: x2 = 4√2x + 6 = 0

x2 = 3√2x - √2x + 6 = 0

x(x - 3√2x) - √2(x - 3√2) = 0

(x - √2) (x - 3√2) = 0

x = √2,3√2.

Answer 2

Answer:

Step-by-step explanation:

Let p (x) = x² - 4√2x + 6 = 0 (Now splitting the middle term )

⇒x² - 3√2x - √2x + 6 = 0 ( ∵-3√2 × (-√2)=3 (√2)² = 3 × 2 = 6; -3√2-√2=-4√2)

⇒x ( x - 3√2 ) - √2 ( x - 3√2 ) = 0 (∵ - √2 × - 3√2 = 3 (√2)² = 3 × 2 = 6 )

⇒ ( x - √2 ) ( x - 3√2 ) = 0

⇒ x - √2 = 0 and x - 3√2 = 0

⇒x = √2 and x = 3√2

∴ The roots of the equation are √2 and 3√2.