what will be the are of the rhombus in cm sq if it's diagonals are integers and it's perimeter is 104cm
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Answer:
here is the answer
Step-by-step explanation:
Let first diagonal be d
Second diagonal be d2
Giver perimeter of a rhombus =20cm
We know perimeter of a rhombus =4sides
Hence, side =420cm=5cm
Now, we know that the diagonals of a rhombus bisect each other at right angles (90°)
Hence, a right angled triangle can be visualized with side as hypotenuse.
Diagonal length =8cm
Half the length ( since diagonal bisect each other ) =28=4cm
⇒(2d)2+(2d2)2=52
⇒(28)2+(2d2)2=25
⇒42+(2d2)2=25
⇒(2d2)2=25−16
⇒(2d2)2
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