Question

What will be the compound interest on Rs.12000 for 3 years, compounded annually at
10%per annum​

Answer 1

Answer:

Compound interest =P(1+10/100)^3

=12000(100+10)^3

100

=12000x110/100x110/100x110/100

=12x11x11x11

=15972

Step-by-step explanation:

If it is right make me brilliant

Answer 2

GiveN:-

• Principal = Rs.12,000
• Time = 3 years
• Rate = 10% per annum

To FinD:-

The Compound Interest.

SolutioN:-

Analysis :

Here the formula for the Compound Interest us used. We have to use the correct formula then substitute the required values in their correct places and calculate. After calculating we will get our answer.

Formula Required :

Compound Interest = [P(1 + R/100)ⁿ] - P

where,

• P is Principal
• R is Rate
• n is time

ExplanatioN:-

We know that if we are given the Principal, Rate and Time and is asked to calculate the Compound Interest compounded annually then our required formula is,

Compound Interest = [P(1 + R/100)ⁿ] - P

where,

• P = Rs.12,000
• R = 10% per annum
• n = 3 years

Using the required formula and substituting the values,

⇒ Compound Interest = [P(1 + R/100)ⁿ] - P

⇒ Compound Interest = [12000(1 + 10/100)³] - 12000

⇒ Compound Interest = [12000(1 + 1/10)³] - 12000

⇒ Compound Interest = [12000(10 + 1/10)³] - 12000

⇒ Compound Interest = [12000(11/10)³] - 12000

⇒ Compound Interest = [12000(11/10 × 11/10 × 11/10)] - 12000

⇒ Compound Interest = [12000 × 11/10 × 11/10 × 11/10] - 12000

⇒ Compound Interest = [12 × 11/1 × 11/1 × 11/1] - 12000

⇒ Compound Interest = [12000 × 11 × 11 × 11] - 12000

⇒ Compound Interest = 15972 - 12000

⇒ Compound Interest = 3972

∴ Compound Interest = Rs.3,972.

Compound Interest is Rs.3,972.

Explore MorE :

• Simple Interest = P × R × T/100
• P = SI × 100/R × T
• R = SI × 100/P × T
• T = SI × 100/P × R
• I = A - P
• A = P + I

where,

• P = Principal
• R = Rate
• T = Time
• SI = Simple Interest
• A = Amount
• I = Interest