Question

What will be the compound interest on rupees 4000 at 5% per annum for 2 years

Answer 1

p=4000
r=5%an
t=2
a=p(1+r/100)^2
a=4000(1+5/100)^2
a=4000(105/100)^2
a=(4000×105×105)/100×100
a=(2×21×105)rs
a=4410rs
ci=a-p
ci=(4410-4000)rs
ci=410rs

Answer 2

Answer:

Step-by-step explanation:

Given details are,

P=RS 4000

R=5%

Time (n)=2 years

By using the formula,

A=p(1+5/100)^n

A=4000(1+5/100)^2

A=4000(105/100)^2

A=RS4410

:. Compound interest=A-P

                                   =4410-4000

                                    =RS410