Question

what will be the concentration of 0.2M of h2so4 solution in g/L​

Answer 1

Answer:

Explanation:

The molecular weight of H₂SO₄ is 98.079 g/mol. So, 98.079 g of H₂SO₄ dissolved in water to give a final volume of 1000 ml gives a 1 M solution. One fifth of this amount of H₂SO₄, 19.616 g, dissolved in 1000 ml gives a 0.2 M solution.

Answer 2

Final answer: Concentration of $0.2$ $M$ of $H_{2}SO_{4}$ solution in $\frac{g}{L}$​ $= 19.6$ $\frac{g}{L}$

Given that: We are given $0.2$ $M$ of $H_{2}SO_{4}$ solution.

To find: We have to find the concentration of $0.2$ $M$ of $H_{2}SO_{4}$ solution in $\frac{g}{L}$.

Explanation:

• The molarity ($M$) of a solution is defined as the number of moles of solute dissolved in the volume of that solution in a liter.

                   $Molarity (M) = \frac{Number of moles of solute (mol)}{Volume of solution in a liter (L)}$

• The concentration of a solution is expressed in molarity.

• Unit of Molarity, $M=\frac{mol}{L}$

        Molarity of $H_{2}SO_{4}$ $=0.2$ $M$ $=0.2$ $\frac{mol}{L}$

• To convert $\frac{mol}{L}$ to $\frac{g}{L}$ we multiply the concentration by the molar mass of the solute ($\frac{g}{mol}$).

• To calculate the concentration of $H_{2}SO_{4}$ solution in $\frac{g}{L}$​ we should multiply molarity with the molarity of $H_{2}SO_{4}$ with the molar mass of $H_{2}SO_{4}$.

• Molar mass of $H_{2}SO_{4}$ $=98$ $\frac{g}{mol}$

• Concentration of $H_{2}SO_{4}$ solution in $\frac{g}{L}$ $= (0.2\frac{mol}{L}) \times 98 \frac{g}{mol}$ $= 19.6$ $\frac{g}{L}$

• Hence, a concentration of $0.2$ $M$ of $H_{2}SO_{4}$ solution in $\frac{g}{L}$​ $= 19.6$ $\frac{g}{L}$

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