what will be the concentration of a solution which is made by mixing 25 ml of 0.2 molarity H2 S 04, 25 ml of 0.25 molarity of H2 s o4, and 45 ml of 0.35 molarity of H2 s o4?
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Answer:
No. of moles in 0.05 liter of H
2
SO
4
= M×V(inliter)
= 0.5×0.05
= 0.025
No. of moles in 0.075 liter of H
2
SO
4
added
= 0.25×0.075
= 0.01875
Total no. of moles in 0.125 liter of H
2
SO
4
= 0.025 + 0.01875
= 0.04375
∴ Molarity of H
2
SO
4
=
0.0125
0.04375
= 0.35 M
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