Question

what will be the cost of making a closed a cone of tin sheet having radius of base 6M and slant height it 8 meter if the rate of making is rupees 10 per square metre?









.friends what I find first

Answer 1

Answer:

Rs. 2639.9 or Rs. 2640 approx...

Step-by-step explanation:

Given base radius = 6 m

Slant height = 8 m

So, We know that Curved Surface Area of Cone = πrl = 22/7 * 6 * 8

= 150.85 cm²

Area of base of cone = πr² = 22/7 * 6 * 6 = 113.14 cm²

Thus, Total Surface Area of Cone = Area of base + CSA = 113.14 + 150.85

= 263.99 or 244 cm² approx

Now, Cost of sheet per sq.m = Rs. 10

So, Total Cost required = Rs. 263.99*10 = Rs. 2639.9 or Rs. 2640 approx...

Answer 2

Total surface area of cone =pi×r×(l+r)
=22/7×6(8+6)
=22/7×6×14
=22×6×2
=44×6
= 264M^2
Now,
=Rs(264×10)
=Rs2640