Question

What will be the current dream by an electric bulb of 40 watts when it is connected to a source of 220 volts.​

Answer 1

✬ Current = 0.18 A ✬

Explanation:

Given:

• Power of bulb is 40W.
• Voltage across the bulb is 220 V.

To Find:

• What current will be drawn ?

Formula to be used:

• Power = Voltage × Current

Solution: Here we have

• P = 40 W
• V = 220 V
• I = to be calculated

Put the values on the values on the formula

$\implies{\rm }$ P = V × I

$\implies{\rm }$ 40 = 220 × I

$\implies{\rm }$ 40/220 = I

$\implies{\rm }$ 4/22 = I

$\implies{\rm }$ 2/11 = I

$\implies{\rm }$ 0.18 A = I

Hence, the current drawn by the bulb will be 0.18 ampere.

• Power is denoted by P , voltage by V and current by I.
• S.I unit of current is ampere denoted by A.

Answer 2

$\purple{\rm Given}\begin{cases} \rm\mapsto \green{ power \: of \: bulb = 40W } \\ \rm \mapsto \orange{connected \: with \: a \: source \: of \: 220V} \end{cases}$

$\red{\rm Find}\begin{cases} \rm\mapsto \pink{what \: current \: will \: be \: drawn = ? } \end{cases}$

$\gray{\rm Solution}$

we, know that

$\underline{\boxed{\to\rm P = VI}}$

$\therefore\rm I = \frac{P}{V}$

where,

• P = 40W
• V = 220V

So,

$\leadsto\rm I = \frac{P}{V}$

$\leadsto\rm I = \frac{4\not{0}}{22\not{0}}$

$\leadsto\rm I = \frac{4}{22} = 0.18A$

$\leadsto\rm I =0.18A$

Hence, the current drawn by an electric bulb of 40W when it is connected to a source of 220V is 0.18A