Question

What will be the differential x relative to the equation x2+2x+2=0

Answer 1

Answer:

2x + 2

Step-by-step explanation:

=d/dx [ (x)^2 +2x + 2]

=d/dx (x)^2 + d/dx (2x) + d/dx (2)

= 2x + 2 +0

= 2x + 2

Answer 2

The other user has already given an assumed differential value for the given problem. The following solution tries to find the value for x.

Step-by-step explanation:

The given equation is $x^{2}+2x+2=0$

Comparing it with the general quadratic equation, we get

• $a=1,b=2,c=2$

Putting the above values in the quadratic formula to find $x$, we can write

$\quad x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

$\Rightarrow x=\dfrac{-2\pm\sqrt{2^{2}-4*1*2}}{2*1}$

$\Rightarrow x=\dfrac{-2\pm\sqrt{4-8}}{2}$

$\Rightarrow x=\dfrac{-2\pm\sqrt{-4}}{2}$

$\Rightarrow x=\dfrac{-2\pm 2i}{2}$ where $i=\sqrt{-1}$

$\Rightarrow x=-1\pm i$

Answer:

The required solutions are $x=-1\pm i$

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