Question

What will be the effect of maximum height of a projectile when is an angle of projectile is changed to 30 to 60 keeping the same initial velocity of projectile

Answer 1

In projectile motion, formula for calculating maximum height is h=(u^2sin^2theta)÷g
by putting the given values of theta we get

for 30°
h1=u^2sin^2 (30°)/g,
h1=u^2/4g

for 60°
h2=u^2sin^2 (60°)/g
h2=3u^2/4g
therefore by comparing both the maximum heights we say that 3(h1)= h2.


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Answer 2

Maximum height = (u^2 Sin^2 θ) / (2g)

If u is kept constant
H ∝ Sin^2 θ

H1 / H2 = Sin^2(30) / Sin^2(60)
H1 / H2 = 1/3

H2 = 3 H1

Maximum height will increase to 3 times that of initial.