Question

. What will be the expenditure of painting the wall up to 5m
rectangular hall of length 15 m and breadth 12 m at the rate of ₹60 per metre square?

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Answer 1

Before, finding the answer. Let's find out on how we can find the answer.

• To find the expenditure, we have to first find the Curved Surface Area. For finding the Curved Surface Area, we have to use the formula of :

$\boxed{\sf CSA \: of \: Cuboid = 2(l + b)h)}$

• Next, we must find the Area of wall. To find that, we must use the formula of :

$\boxed{\sf Area \: of \: wall = l \times b}$

• Then, we must add the Curved Surface Area and Area of Wall.
• At last, multiply with the rate.

________________________

Given :

• Length = 15 m
• Breadth = 12 m
• Height = 5 m
• Rate = ₹60

To find :

• expenditure of painting

Solution :

Curved Surface Area = 2(l + b)h

                                   = 2(15 + 12) × 5

                                   = 2 × (27) × 5

                                   = 2 × 135

                                   = 270 m²

∴ Curved Surface Area is 270 m².

Area of wall = l × b

                    = 15 × 12

                    = 180 m²

∴ Area of wall is 180 m².

Total Area = Curved Surface Area + Area of wall

                 = 270 + 180

                 = 450 m²

Expenditure = Total Area × Rate

                    = 450 × 60

                    = ₹ 27000

∴ Expenditure for painting is ₹ 27000.

Answer 2

Step-by-step explanation:

Curved Surface Area = 2(l + b)h

= 2(15 + 12) × 5

= 2 × (27) × 5

= 2 × 135

= 270 m²

∴ Curved Surface Area is 270 m².

Area of wall = l × b

= 15 × 12

= 180 m²

∴ Area of wall is 180 m².

Total Area = Curved Surface Area + Area of wall

= 270 + 180

= 450 m²

Expenditure = Total Area × Rate

= 450 × 60

= ₹ 27000

∴ Expenditure for painting is ₹ 27000.

hopefully it will work ☺️☺️