Math, asked by rsunilkumar237pbj45i, 1 year ago

What Will be the factors of X³-27?

Answers

Answered by siddhartharao77
95
Given Equation is x^3 - 27

= > (x^3) - (3)^3

We know that a^3 - b^3 = (a - b)(a^2 + b^2 + ab)

= > (x - 3)(x^2 + 3^2 + 3x)

= > (x - 3)(x^2 + 9 + 3x)


Therefore the factors of x^3 - 27 are (x - 3) (x^2 + 9 + 3x).


Hope this helps!

siddhartharao77: :-)
rsunilkumar237pbj45i: Super and
Answered by Dhruv4886
3

Factors of (X³-27) are  (X-3) (X²+9+3X)  

Given:

X³-27

To find:

Factors of X³-27  

Solution:

Given X³-27

As we know 3³ = 27  

X³-27 = (X³ - 3³)  

From algebraic identities

             (a³-b³) =(a-b)(a²+b²+ab)

Take a = X and b = 3 and apply above formula

(X³ - 3³) = (X-3) [ X²+3²+3(X) ]  

             = (X-3) [ X²+9+3X ]    

Factors of (X³-27) are  (X-3) (X²+9+3X)  

#SPJ2

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