What Will be the factors of X³-27?
Answers
Answered by
95
Given Equation is x^3 - 27
= > (x^3) - (3)^3
We know that a^3 - b^3 = (a - b)(a^2 + b^2 + ab)
= > (x - 3)(x^2 + 3^2 + 3x)
= > (x - 3)(x^2 + 9 + 3x)
Therefore the factors of x^3 - 27 are (x - 3) (x^2 + 9 + 3x).
Hope this helps!
= > (x^3) - (3)^3
We know that a^3 - b^3 = (a - b)(a^2 + b^2 + ab)
= > (x - 3)(x^2 + 3^2 + 3x)
= > (x - 3)(x^2 + 9 + 3x)
Therefore the factors of x^3 - 27 are (x - 3) (x^2 + 9 + 3x).
Hope this helps!
siddhartharao77:
:-)
Answered by
3
Factors of (X³-27) are (X-3) (X²+9+3X)
Given:
X³-27
To find:
Factors of X³-27
Solution:
Given X³-27
As we know 3³ = 27
X³-27 = (X³ - 3³)
From algebraic identities
(a³-b³) =(a-b)(a²+b²+ab)
Take a = X and b = 3 and apply above formula
(X³ - 3³) = (X-3) [ X²+3²+3(X) ]
= (X-3) [ X²+9+3X ]
Factors of (X³-27) are (X-3) (X²+9+3X)
#SPJ2
Similar questions
Computer Science,
7 months ago
Social Sciences,
7 months ago
English,
1 year ago
English,
1 year ago
Physics,
1 year ago
Math,
1 year ago