What will be the final concentration of 0.1M
H₂SO4 solution if it is diluted to 1000 times?
Answers
Answered by
0
Answer:
0.2 M H2SO4 = 0.4 N H2SO4
N1V1 = N2V2
0.4 x 1 = N2 x 1000
N2 = 0.0004 N
Answered by
2
Answer:
No of moles of H2SO4 in 50 mL of 0.5 M
- = 0.5 x50 /1000 = 25 /1000
No of moles of H2SO4 in 150 mL of 0.25
- = 0.25 × 150 / 1000=37.5/1000
= 0.25 × 150 / 1000=37.5/1000Total moles in mixture = 25/1000 + 37.5 /1000
- = 0.25 × 150 / 1000=37.5/1000Total moles in mixture = 25/1000 + 37.5 /1000= 62.5/1000
= 0.25 × 150 / 1000=37.5/1000Total moles in mixture = 25/1000 + 37.5 /1000= 62.5/1000Volume of the final mixture = 250 mL = 0.25 L
= 0.25 × 150 / 1000=37.5/1000Total moles in mixture = 25/1000 + 37.5 /1000= 62.5/1000Volume of the final mixture = 250 mL = 0.25 LMolarity of 250 mL mixture = 62.5/1000 ÷ 0.25
- = 0.25 × 150 / 1000=37.5/1000Total moles in mixture = 25/1000 + 37.5 /1000= 62.5/1000Volume of the final mixture = 250 mL = 0.25 LMolarity of 250 mL mixture = 62.5/1000 ÷ 0.25= 0.25 M
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