Question

What will be the H-Cl bond enthalpy, if enthalpy of dissociation of HCl molecule is 431.9 kJ?
1) 215.5 kJ
2) -215.5 kJ
3) 431.9kJ
4) -431.9 kJ​

Answer 1

Answer:

both are same - 431 J..it is the amount of energy released

Answer 2

To find :

The H-Cl bond enthalpy, if enthalpy of dissociation of HCl molecule is 431.9 kJ.

Calculation:

Bond enthalpy and Bond-Dissociation Enthalpy are same energy quantities , which is defined as the average energy stored in between atoms of a bond.

• In other words , it is the average amount of energy required to break that specific bond between the atoms.

So, bond enthalpy be E:

$\boxed{ \bf{E = + 431.9 \: kJ}}$

• The sign for this energy is positive as this energy has to be supplied from external sources inorder to break the bond.