Question

What will be the h+ concentration in a solution prepared by mixing 50ml of 0.?

Answer 1

Answer:

50 ml (0.2) = 0.01 mol NaCl

25 mL (0.1) = 2.5 x 10–3mol NaOH

25 mL (0.3) = 7.5 x 10–3 mol HCl

NaCl Will is neutral

neutralization between

HCl + NaOH = NaCl + H2O

1 mol neutralises 1 mol NaOH

7.5 x 10–3 - 2.5 x 10–3 = 5 x 10–3 (HCl) not neutralized)

Total volume of the solution:

50 mL + 25 mL + 25 mL

118 mL

[H] = 5 x 10–3 / 0.100 L = 0.05mol/L