What will be the h+ ion cocentration when 4g naoh dissolved in 1000ml of water?
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At first, calculate the [OH-] because [H+] [OH-] = 1 x 10-14.
Given,
amount of solute = 4 g
molar mass of NaOH = 40 g
Vol. of water = 1000 ml =. 1 litre
Now, applying the formula of Molarity for calculating [OH]- , we get
[OH]- = 4/40 x 1
=0.1 mol/litre
Now,
[H]+[OH]- = 1 x 10-14
[H]+ = 1 x 10-14 / 0.1
=1 x 10-13 M
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