Question

What will be the initial rate of a reaction if its rate constant is 10^-3 min^-1. and the concentration of
reactant is 0.2 mol dm^-3. How much of reactant will be converted into products in 200 min
a) 2 x 10^-4M min^-1, 18%
b) 10^-4M min^-1, 16%

c) 10^-3M min^-1, 18%
d) 10^-3M min^-1, 17%

question for brainly stars and moderators​

Answer 1

Answer:

Rate =K×[A]

=10−3×0.2=2×10−3moldm−3min−1

200=10−32.303log(0.2−x0.2)

0.244−1.22x=0.2

x=0.036moldm−3