Question

what will be the kinetic energy of a 100gm mass object 3 second after it starts to fall unimpeded from a height of 500m?​

Answer 1

Answer:

Firstly we need to find the velocity

Using ,

v = u + gt

Where

v : final velocity

u : Initial velocity

g : acceleration due to gravity

t : time

v = 0 + 10(3)

→ v = 30 m/s

__________________________

Now , coming to the question

As we know that

K.E = 1/2 mv²

Where

K.E : kinetic energy = ?

m : mass of object = 100g = 0.1 kg

v : velocity = 100 m/s

Substituting the values we have

→ K.E = 1/2 × 0.1 × 30 × 30

→ K.E = 0.1 × 15 × 30

→ K.E = 450 × 0.1

→ K.E = 45 kgm/s or J

Hence , kinetic energy ( K.E ) = 45J