Math, asked by ajay17871, 11 months ago

what will be the least possible number of the plank ,if three pieces of timber 42m,49,and63m long have to be divided into planks of the some length?

Answers

Answered by IRONMAN2910
3

Answer:

7

Step-by-step explanation:

we have to find the HCF of these three no.

first of two no. - 49, 42 .

49=42×1+7.

42=7×7+0.

H.C.F.= 7

now HCF of the third no. and the hcf we have find i.e 7

63=7×9+0.

hence the HCF is 7.

7 is the least possible no of planks .

Similar questions