what will be the least possible number of the plank ,if three pieces of timber 42m,49,and63m long have to be divided into planks of the some length?
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Answer:
7
Step-by-step explanation:
we have to find the HCF of these three no.
first of two no. - 49, 42 .
49=42×1+7.
42=7×7+0.
H.C.F.= 7
now HCF of the third no. and the hcf we have find i.e 7
63=7×9+0.
hence the HCF is 7.
7 is the least possible no of planks .
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