What will be the least possible number of the planks, if three pieces of timber 42 m, 49 m and 63 m long have to be divided into planks of the same length?
Answers
Answered by
5
Answer:
by taking a L.C.M we get 7×2×3×3×7 = 882
answer is 882
Answered by
14
Answer:
7
Step-by-step explanation:
we have to find the HCF of these three no.
first of two no. -49,42
49 =42 into1+7
42=7 into 7+0
HCF 7
now HCF of the third no. and the HCF we have find i.e =7
63=7 into 9+0
hence the HCF is 7
7 is the least possible no. of plank
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