Question

plz solve
,,,,,as fast as possible

Answer 1

sin@=3/4,

here
perpendicular=3k,
hypotenuse=4k,

then

base=√(16k²-9k²)=√7k,


therefore

√[(cosec²@-cot²@)/(sec²@-1)],


√(1/tan²@),

√cot²@,

cot@,


then

cot@=base/perpendicular,

√7k/3k,

√7/3

Answer 2

hey mate
here's the solution