Question

What will be the longest wavelength line in balmer series of spectrum of hydrogen atom?

Answer 1

Answer:

Since wavelength and energy are inversely related, the longest wavelength would be produced by the lowest amount of energy. That would be by the electron falling from from n = 3 (ni) to n = 2 (nf). (All Balmer series lines have nf = 2). lambda = 1 / (1.52 x 10^6 m) = 6.56 x 10^-7 m = 656 nm . . .that's a RED line.

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Answer 2

Explanation:

For single electron species,

λ

1

=RZ

2

(

n

1

2

1

−

n

2

2

1

)

where, R = Rydberg constant = 1.097×10

7

×10

−9

nm

−1

=1.097×10

−2

nm

−1

For Hydrogen atom, Z = Atomic number = 1

For Balmer series, n

1

= 2 and for longest wavelength in Balmer series, minimum energy transition is to be considered because wavelength is inversely proportional to Energy.

So, n

2

= 3

∴

λ

1

=1.097×10

−2

nm

−1

×1

2

(

2

2

1

−

3

2

1

)

⇒λ=656nm

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