Physics, asked by abinopoulose8301, 11 months ago

What will be the magnitude and direction of the reaction force acting on a coin of 10 g lying on the surface of the floor? Take g = 9.8 m/s2

Answers

Answered by gadakhsanket
58

Dear Student,

◆ Answer -

Reaction force = 0.098 N in upward direction

● Explanation -

# Given -

m = 10 g = 0.01 kg

# Solution -

Reaction force acting on the coin is -

F = m × a

F = m × (-g)

F = 0.01 × (-9.8)

F = -0.098 N

Hence, reaction force acting on the coin is 0.098 N in upward direction.

Thanks dear. Hope this is helpful to you...

Answered by Anonymous
8

Answer:

◆ Answer -

  • Reaction force = 0.098 N in upward direction

● Explanation -

# Given -

  • m = 10 g = 0.01 kg

# Solution -

Reaction force acting on the coin is -

F = m × a

F = m × (-g)

F = 0.01 × (-9.8)

F = -0.098 N

Hence, reaction force acting on the coin is 0.098 N in upward direction.

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