what will be the magnitude of change in momentum imparted by the floor to a ball of mass 1 kg if it falls from the height of 100 cm on the floor and rebound vertically upward with same speed?
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Answer:
2.8kgm/s
Explanation:
m=1kg, h=100cm = 0.1m
use, v² = 2gh
v² = 2x9.8x0.1 = 1.96
v = √1.96 = 1.4m/s
change in momentum = mv-(-mv) = 2mv
= 2x1x1.4kgm/s = 2.8kgm/s.
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