Question

what will be the mass of 0.05 moles of feso4.7h2o

Answer 1

Hello Dear.

Here is the answer---

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Given ⇒

Number of Moles of FeSO₄.7H₂O = 0.05

Molar mass of the FeSO₄.7H₂O = 278 g/mole.


Using the Formula,

 Number of Moles = Mass/Molar mass
⇒ Mass = Number of Moles × Molar Mass
              = 0.05 × 278
              = 13.9 g.


Thus, the Mass of the 0.05 moles of FeSO₄.7H₂O is 13.9 grams.


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Hope it helps.

Have a Good Day.

Answer 2

First of all we have to find molecular mass of FeSO₄.7H₂O
Atomic mass of Fe = 56 g/mol
atomic mass of S =32g/mol
Atomic mass of O = 16g/mol
Atomic mass of H = 1g/mol

Now, molecular mass of FeSO₄.7H₂O = 56 + 32 + 4 × 16 + 7(2 × 1 + 6)
= 88 + 64 + 126
= 278 g/mol

∵mole of substance = weight of substance/molecular weight of substance
∴ 0.05 = weight of FeSO₄.7H₂O/278
0.05 × 278 = weight of FeSO₄.7H₂O
Weight of FeSO₄.7H₂O = 13.9 gm

Hence, answer is 13.9 gm