What will be the maximum number of lines possible for balmer series when a set of 8hydrogen atoms are irradiated with light and all are excited to 6th excited state and spectrum is obtained?
Answers
Answered by
5
for 1 hydrogen atom, no. of spectral lines is given by
N = (n2-n1)(n2-n1+1)/2
here,n1= 2 and n2= 7
n2 will be 7 as it is the 6th excited state
therefore,
N=(7-2)(7-2+1)/2 = 5×6/2 = 15
therefore, for 8 hydrogen atoms maximum no. of lines are 8×15 = 120 lines
N = (n2-n1)(n2-n1+1)/2
here,n1= 2 and n2= 7
n2 will be 7 as it is the 6th excited state
therefore,
N=(7-2)(7-2+1)/2 = 5×6/2 = 15
therefore, for 8 hydrogen atoms maximum no. of lines are 8×15 = 120 lines
Answered by
14
Answer:5
Explanation:
6th excited state refers to the 7th energy level and balmer series refers to the 2nd energy level, so moving on from 7th energy level to the 2nd energy level, we will obtain 5 different sprectral lines
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