Question

What will be the minimum diameter of a steel wire, which is used to raise a load of 4000N if the stress in the rod is not to exceed 95 MN/m2?

Answer 1

Diameter of steel wire would be 7.3 mm

It has given that a steel of wire is used to raise a load of 4000N if the stress in the rod is not to exceed 95 MN/m²

we have to find the minimum diameter of the steel wire.

using formula, stress = load/cross sectional area

⇒ 95 MN/m² = 4000/A

⇒95 × 10^6 = 4000/A

⇒A = 4000/(95 × 10^6) = 4/95000 ≈ 0.0000421 m²

let diameter of steel wire is d

so cross sectional area A = πd²/4

0.0000421 = (3.14 × d²)/4

⇒4 × 0.0000421 = 3.14 × d²

⇒d² = (4 × 0.0000421)/3.14 = 0.0000536

⇒d = 0.0073 ≈ 7.3 mm

therefore, diameter of steel wire is 7.3 mm

Answer 2

Answer:

Explanation:

7.3mm