Question

What will be the minimum pressure required to compress 500 dm cube of air at 1 bar to 200 dm cube at 30 degree C ?

Answer 1

Hi

Here is your answer,

P₁ = 1 
P₂ = ?

V₁= 500 dm³
V₂= 200 dm³

Apply boyle's law  p₁V₁=p₂V₂ to calculate p₂ as temperature remains constant.

p₂ = p₁V₁/ V₂ = 1 bar × 500 dm³/ 200 dm³ = 2.5 bar

2.5 is the required answer ! 

Hope it helps you !

Answer 2

Hi friend,

Your answer:

By applying Boyle's Law,

 p₁V₁=p₂V₂ 

=> p₂ = p₁V₁/ V₂                          (Temperature remains constant)

          = 1 bar × 500 dm³/ 200 dm³

          = 2.5 bar

Hence, 2.5 bar is the minimum pressure required to compress 500 dm cube of air at 1 bar to 200 dm cube at 30 degree C.

Hope it helps!