Question

What will be the minimum pressure required to compress 500 dm³ of air at 1 bar to 200 dm³ at 30 degree Celsius?? ​

Answer 1

$\huge\bf\mathbb\pink{HELLO }$

Here is your answer,

P₁ = 1 
P₂ = ?

V₁= 500 dm³
V₂= 200 dm³

Apply boyle's law  p₁V₁=p₂V₂ to calculate p₂ as temperature remains constant.

p₂ = p₁V₁/ V₂ = 1 bar × 500 dm³/ 200 dm³ = 2.5 bar

2.5 is the required answer ! 

Hope it helps you !✌✌✌

Answer 2

$\huge\mathfrak{Solution}$

Given that :

P1 = 1 bar

P2 = ?

V1 = 500 dm³

V2 = 200 dm³

Here Temperature remains constant so according to Boyle's Law,

P1V1 = P2V2

P2 = P1V1 / V2

P2 = 1(bar) * 500(dm³) / 200(dm³)

P2 = 2.5 bar.

Hope it helpful to you mate if you satisfy then please mark me as ☺ ☺ ✌ ✌