What will be the molarity of 0.1 molal h2so4 solution having density 1.2 g/ml?
Answers
Answered by
3
Molality of the solution = 0.1
This means, no. of moles of the sulphuric acid in 1 kg of the solution is 0.1
Density of the solution = 1.2 g/ml.
This, means,
Density = Mass/Volume
1.2 g/ml. = 1000g/ Volume
∴ Volume = 1000/1.2
∴ Volume = 833.33 mL. = 0.83 L.
Now, Molarity = No of moles/Volume of solution
∴ Molarity = 0.1/0.83
∴ Molarity = 0.12 M.
Hope it helps.
Answered by
5
Answer:
Question :-.
- What will be the molarity of 0.1 molal h2so4 solution having density 1.2 g/ml?
Solution :-
. Density of the solution = 1.2 g/ml.
∴ Volume = 833.33 mL.
= 0.83 L.
Similar questions