Question

What will be the mole fraction of water in methanol solution containing equal number of moles of water and methanol?

Answer 1

Methanol = CH4 O or CH3 OH
molar mass of methanol: 12+4+16=32
=> 3.2 gram = 0.1 moles
18 grams of water => 1 mole of water as molar mass of water is 18.
total number of moles in the solution = 1.1
so molar fraction of methanol in the solution = 0.1 /1.1 = 9.99%
of 0.0999

Answer 2

Concept:

The number of moles of a particular component in the solution divided by the overall number of moles in the sample solution is known as the mole fraction.

Given:

The equal number of moles of water and methanol.

Find:

What will be the mole fraction of water in a methanol solution containing an equal number of moles of water and methanol?

Solution:

Let the number of moles of water and methanol be x.

The mole fraction of A can be calculated as:

Mole fraction of A = number of moles of  A / Number of moles of solute (A + B)

Now,

Mole fraction of water = number of moles of water / Number of moles of solute (water + methanol)

= x / (x+x) = x/ 2x = 1/2 = 0.5

Mole fraction of methanol = number of moles of methanol / Number of moles of solute (water + methanol)

= x / (x+x) = x/ 2x = 1/2 = 0.5

Hence, the mole fraction of water in a methanol solution containing an equal number of moles of water and methanol is 0.5.

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