Question

What will be the molecular formula of the
compound with empirical formula CH2Cl
and molar mass 98.96g​

Answer 1

Answer:

Molecular formula = C₂H₄Cl₂

Explanation:

$\blacksquare$ Empirical formula is defined as the simplest formula of a compound where the common factors between number of atoms is cancelled out

$\blacksquare$ For example , butane $\implies$ C₄H₁₀ (Molecular formula)

         empirical formula $\implies$ C₂H₅ (Common factor 2 is cancelled)

$\blacksquare$ Given that,

Empirical formula = CH₂Cl

Molecular formula mass = 98.96 g

Empirical formula mass = 12 + 2 + 35.5

                                       = 49.5 g

$\blacksquare$ We know that,

Common factor = n = $\dfrac{Molecular \ formula \ mass}{Empirical \ formula \ mass}$

Molecular Formula = n * (Empirical Formula)

Hence,

n = $\dfrac{98.96}{49.5} = 1.99 \approx 2$

Therefore,

Molecular Formula = 2 * (CH₂Cl)

Molecular Formula = C₂H₄Cl₂