Question

what will be the net acceleration of the given block of mass 2kg kept on a smooth surface?

Answer 1

total force is (12+10)-20=2N f=ma a=2/2=1m/sec*2

Answer 2

Answer:

The net acceleration of the given block of mass 2kg kept on a smooth surface will be 1 m/s².

Explanation:

The acceleration acting on the block is calculated as,

$\mathrm{a=\frac{F}{m} }$               (1)

Where,

a=net acceleration on the given block

F= net force acting on the block

m=mass of the block

The net force on the block is calculated as,

$\mathrm{F=F_1-F_2}$        (2)

F₁= net force acting on the right side of the block

F₂=net force acting on the left side of the block

So,

F₁=10+12=22 N          (3)

F₂=20 N                     (4)

Inserting the value of F₁ and F₂ in equation (2) we get;

$\mathrm{F=22-20}$

$\mathrm{F=2\ N}$        (5)

By inserting the value of "F" and "m" in equation (1) we get;

$\mathrm{a=\frac{2}{2} }$

$\mathrm{a=1\ m/s^2}$

So, the net acceleration of the given block of mass 2kg kept on a smooth surface will be 1 m/s².

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