Question

What will be the net resultant force in both the situations given below?

Answer 1

Answer:

Basically , net force is known as resultant force and is a vector quantity.

In the Attachment b) it is net resulant force because they both boys are pulling it.

In the Attachment a ) It's difficult to say that it's net resulant or not .

Because from both sides the boys are pulling and wasting their energy.

Hence, attachment b is a net resulant force in the situations given below .

Answer 2

Answer

(a) 0 N

(b) 2F N

Given

Case - 1 :

• Two boys are pulling the cart in opposite direction .

Case - 2 :

• Two boys are pulling the cart in same direction .

To Find

• Net resultant force in both cases

Solution

→ Case - 1 :  (a)

[ Assume that forces exerted by two boys will be same i.e., F ]

Let the force exerted by boy 1 be F₁

⇒ F₁ = F

[ ∵ He pulls cart in  + ve direction ]

Let the force exerted by boy 2 be F₂

⇒ F₂ = - F

[ ∵ He pulls cart in - ve direction ]

So ,

Net resultant force ,

$\rm F_{net}=F_1+F_2\\\\\implies \rm F_{net}=F+(-F)\\\\\implies \rm F_{net}=F-F\\\\\implies \rm F_{net}=0\ N\ \bigstar$

→ Case - 2 : (b)

[ Assume that forces exerted by two boys will be same i.e., F ]

Let the force exerted by boy 1 be F₁

⇒ F₁ = F

[ ∵ He pulls cart in  + ve direction ]

Let the force exerted by boy 2 be F₂

⇒ F₂ =  F

[ ∵ He too pulls cart in + ve direction ]

So ,

$\rm F_{net}=F_1+F_2\\\\\implies \rm F_{net}=F+(F)\\\\\implies \rm F_{net}=F+F\\\\\implies \rm F_{net}=2F\ N\ \bigstar$