Question

what will be the number of real zeros of the polynomial X square + 1

Answer 1

Rmthe answer will be two( -1) and 1

Answer 2

It has no real roots as

X2 + 1 = 0
Here a=1 , b=0 and c= 1

D = b2 - 4ac
D=0*2 - 4*1*1
D=0-4
D=-4

If D < 0, then it has no real roots.