What will be the output of following relations if
d = 20 initially?
(i) + + d<=20
(ii) d + + <=20
(iii) + + d<= 35
(iv) (+ + d) *10>d
Answers
Answer:-
Note:-
- The above question relational operator is there so it will return the answer in either true or false.
Let us solve..!
Given, d=20
- ++d<=20
Now 21<=20, condition is false.. so it will return false
- d++ <=20
Note: here will not increase now because d++ is postfix increment
Now 20<=20 , condition is true.. so it will return true
- ++d<=35
21<=35, condition is true.. so it will return true
- (+ + d) *10>d
Well, lets solve it first
(++d)*10>d
(++20)*10>10
(21)*10>10
210>10
Now is 210>10? yes 210 is greater than 10 so it will return true.
Answer:
• ++d<=20
Now 21<=20, condition is false.. so it will
return false
d++ <=20
Note: here will not increase now because
d++ is postfix increment
Now 20<-20, condition is true.. so it will
return true
• ++d<=35
21< 35, condition is true.. so it will return
true
(++ d) *10>d
Well, lets solve it first
(++d)*10>d
(++20)*10>10
(21)*10>10
210>10
Now is 210>10? yes 210 is greater than 10 so
it will return true.
Explanation:
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