Question

What will be the output of the program #includeint main () {int x=12,y=7 z;z=x!=4||y==2;printf("z=%d\n",z);return 0;}

Answer 1

Answer:

1

Explanation:

value of z will be 1.

Because x!=4 means x is not equal to 4 which is true condition and it's value is set to be 1

y==2 which is false and value set tobe 0

finally 1||0 that is 1 or operator with 0 is 1

that's why answer is 1