کن
What will be the path of a charged particle projected along a magnetic field ?
2
2
Answers
Answer:
The direction of magnetic field is along the direction of motion of the charge particles, so angle will be 0∘.
∴ Force F=qvBsinθ
=qvBsin0
=0(∵sin0=0)
So, there will be no change in the velocity.
If we tend to contemplate that the charge was initially moving linearly, then it'll still move in this same direction with no deviation.
Explanation:
To find:
The Path over charged particle projected on the flux?
Calculation:
The general expression of force fully fledged by a moving charge particle is given as :
\therefore \: \vec = q( \vec \times \vec)∴
F
=q( v × B )
{\implies \: | \vec | = alphabetic character \times v \times B \times \sin( \theta) }}
⟹ F
=q×v×B×sin(θ)
Here "F" is force , "q" is charge , "v" is rate , "B" is flux intensity and \thetaθ is that the angle between rate vector and field strength vector.
When the charged particle is moving on the direction of flux intensity , we are able to say that \theta = ^θ=0
Putting the on the market values:
\implies \: | \vec| = alphabetic character \times v \times B \times \sin( ^ )⟹∣
F
=q×v×B×sin(0∘)
\implies\: | \vec| = zero \: N⟹∣
F
=0N
So, the moving charged particle doesn't expertise any force.
Hence, if we tend to contemplate that the charge was initially moving linearly, then it'll still move in this same direction with none deviation.