What will be the percentage increaze in temperature if volume is increased by 20%?
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According to Charles Law,
V/T = V'/T'
Here ,let's assume that the V = 100
Even T = 100
The volume increases by 20%
This means V' = 100 + 20 = 120
T' = ?
So plug the values in the expression.
100/100 = 120/T'
T' = 120
Initial temperature = 100
Final temperature = 120
So % increase in temperature
= (120 -100)/100 x 100%
= 20/100 x 100%
= 20%
So your required answer is 20%
Hope This Helps You!
V/T = V'/T'
Here ,let's assume that the V = 100
Even T = 100
The volume increases by 20%
This means V' = 100 + 20 = 120
T' = ?
So plug the values in the expression.
100/100 = 120/T'
T' = 120
Initial temperature = 100
Final temperature = 120
So % increase in temperature
= (120 -100)/100 x 100%
= 20/100 x 100%
= 20%
So your required answer is 20%
Hope This Helps You!
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