Question

What will be the period of oscillation if the length of a simple pendulum is halved?

Answer 1

T=2π√l/g

l'=l/2

T'=2π√l/2/g

T'=T/√2

therefore new time period will be 1/√2 times lesser than the original one

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Answer 2

ANSWER:___✍️

The equation for simple pendulum is T = 2pi*SQRT(L/g)

so if the pendulum length is halved then the length l should be change to half the length L/2 which gives you the solution finally to

T1=sqrt2*pi*sqrt(L/g) Let this be equal to T1

that results in time periodT1 to be 72% of the original time period (when length is L)

T1=0.72(T)