What will be the perpendicular distance of point (-4,3) form x-axis?
Anonymous:
3 units
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Hi Mate!!!
equation of x -axis is y= 0
let the perpendicular distance be = d
d = 0 ( -4 ) + 1 ( 3 ) + 0 / √ ( 0+ 1 )
d = 3 units.
................................................
if the equations of line is
ax + by + c = 0 at ( x1 , y1)
perpendicular distance =
ax1 + by1 + c / √ ( a² + b² )
equation of x -axis is y= 0
let the perpendicular distance be = d
d = 0 ( -4 ) + 1 ( 3 ) + 0 / √ ( 0+ 1 )
d = 3 units.
................................................
if the equations of line is
ax + by + c = 0 at ( x1 , y1)
perpendicular distance =
ax1 + by1 + c / √ ( a² + b² )
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