What will be the PH of 0.002 MHcl
Answers
Answered by
22
PH=-log[H+]
=-log(2×10^-3)
=3-log2
=3-0.301
=2.699
PLEASE MARK BRAINLIST.
ENJOY☺☺
=-log(2×10^-3)
=3-log2
=3-0.301
=2.699
PLEASE MARK BRAINLIST.
ENJOY☺☺
Answered by
7
[HCl] = 0.002
This is stoichiometric with [H₃O]
pH = - log [H₃O]
= - log (2*(10⁻³))
= -0.3010 + 3
= 2.699
= 2.7
Therefore pH is 2.7
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