Question

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what will be the power consumption of two 300 W bulbs,three 100 W fans and one 1200 W refrigerator for continuous operation of 30 hours ?

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Answer 1

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HERE IS UR ANSWER

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Given

• two bulbs=300W

power of two bulbs = 600 W

• three fans=100W

power of 3 fans=300W

• one refrigerator=1200 W
• total time= 30 hours

Solution

energy = power × time

$power = \frac{energy}{time}$

total power= sum of all powers

= (600+300+1200)W=2100W

power consumption=1200W × 30 hrs

=63000 Wh

we know 1kWh=1000Wh

so,power consumed in 30 hrs=63kWh