Question

What will be the pressure in dyne/cm^2, due to a water column of height 12.5 cm ?(g=980 cm/s^2)(density of water 1000 kg/m^3). 1)1.225*100 dyne/cm^2.
2)1.225*1000dyne/cm^2
3)1.225*10000dyne/cm^2
4)1.225*100000dyne/cm^2​

Answer 1

Answer:

1.225*10000dyne/cm^2

Explanation:

pressure =dgh

=>980*12.5*10^6/10^6g/cm^3

hence pressure =12250dyne/cm^2

therefore answer =1.225*10000dyne/cm^2

hope it will help you!!!

Answer 2

Pressure, $P=1.225\times 10000\ dyne/cm^2$

Explanation:

Given that,

The density of water, $d=1000\ kg/m^3$

Height, h = 12.5 cm = '0.125 m

Acceleration due to gravity, $g=980\ cm/s^2=9.8\ m/s^2$

The pressure due to a water column is given by :

$P=dgh$

$P=1000\times 9.8\times 0.125$

P = 1225 Pa

Since, $1\ Pa = 10\ dyne/cm^2$

$P=12250\ dyne/cm^2$

or

$P=1.225\times 10000\ dyne/cm^2$

So, the correct option is (3). Hence, this is the required solution.

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