Question

what will be the pressure of the gas mixture when 0.5l of H2 at 0.8bar and 2.0l of oxygen at 0.7bar are introduced in a 1l vessel at 27°c ?​

Answer 1

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Answer 2

Answer:

Explanation:

From the equation Pv = n RT for the two gases. We can write

0.8 x 0.5 = nH2 x RT  or nH2  = 0.8 x 0.5 / RT

ALSO  0.7 x 2.0  = n02 . RT  or n02  = 0.7 x 2 / RT

When introduced in 1 L vessel, then

Px1L = (n02 + nH2)  RT

Putting the values, we get

P = 0.4 + 1.4 = 1.8 bar

Hence, the total pressure of the gaseous mixture in the vessel is 1.8 bar